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firebase-ios-sdk/FirebaseAI/Sources/Protocols/Public/LanguageModel.swift
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Swift

// Copyright 2026 Google LLC
//
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
#if compiler(>=6.2.3)
public extension FirebaseAI {
/// A type that represents a large language model (LLM).
protocol LanguageModel: LanguageModelProvider {
/// Returns the name of the model.
///
/// > Important: This property is for **internal use only** and may change at any time.
var _modelName: String { get }
/// Returns a new session for this model.
///
/// > Important: This method is for **internal use only** and may change at any time.
func _startSession(tools: [any ToolRepresentable]?, instructions: String?) throws
-> any _ModelSession
}
}
// Default implementation to allow a `FirebaseAI.LanguageModel` to conform to
// `LanguageModelProvider`.
public extension FirebaseAI.LanguageModel {
func _languageModel(firebaseAI: FirebaseAI) -> any FirebaseAI.LanguageModel {
// A `FirebaseAI.LanguageModel` can simply provide itself since it is already a
// `FirebaseAI.LanguageModel`.
return self
}
}
#endif // compiler(>=6.2.3)